- #1
jaron
- 23
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Homework Statement
the critical angle for a ray of light leaving an unknown material (surrounded by air) is
32.4'(degrees celcius). the speed of light in the material is:
Homework Equations
niSin(theda)c = nRSin(theda)R
(i am not sure how to make theda symbols on the computer)
The Attempt at a Solution
niSin32'/Sin32' = 1Sin90'/Sin32'
ni = 1/0.53
ni = 1.89x10^8 m/s
that's the answer that makes the most sense to me. but the back of my book has a different answer:
1.61x10^8 m/s (i have no idea how they got this)
i have a test on this stuff tomorrow