- #1
Leb
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Homework Statement
Problem is described in the picture
I do not understand how can [itex]\alpha^{'}R=a^{'}[/itex].
The dimensions do not seem correct. Angular velocity x distance from the origin = tangential velocity, is that correct ? How can this equal acceleration then ?
3. Attempt to solution
I think that [itex]\alpha^{'}R=a^{'}[/itex] would hold only if we would consider a unit time. That is:
[itex]\alpha^{'}R=\frac{d\theta}{dt}R[/itex], which, more by knowing the anticipated result in this case, than by logic, gives [itex]\frac{d\theta}R = a^{'}dt[/itex] which is now dimensionally OK, I think...
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