- #1
kidia
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Hi I have a question
A baseball player hits a baseball that lands in stands 24 meters above the playing field.The ball land with velocity of 50 meters per second at angle of 35 degree below the horizontal.
a.If a player hits the ball 1 meter above the playing field,what was the velocity of the ball upon leaving the bat?
b.What was the horizontal distance traveled by ball
c.how long was the ball in air
I have done like this:
let r be angle in degrees
t=2usinr/g
time=?
velocity=50m/s
gravity=10
time= 2*50*sin35/10=5.74s
velocty of ball at 1m will be:
y=vsinrt-0.5gt
1=usin35*5.74-0.5*10*5.74*5.74
u=50.61m/s
b.horizontal distance traveled by ball
distance/time=velocity
then
distance/time=ucosr
distance=50cos35*5.74
distance=235m
c.Time of the ball in air.
t=2usinr/g
time=?
unitial velocity=50m/s
gravity=10
time= 2*50*sin35/10=5.74s
Any idea about this question?
A baseball player hits a baseball that lands in stands 24 meters above the playing field.The ball land with velocity of 50 meters per second at angle of 35 degree below the horizontal.
a.If a player hits the ball 1 meter above the playing field,what was the velocity of the ball upon leaving the bat?
b.What was the horizontal distance traveled by ball
c.how long was the ball in air
I have done like this:
let r be angle in degrees
t=2usinr/g
time=?
velocity=50m/s
gravity=10
time= 2*50*sin35/10=5.74s
velocty of ball at 1m will be:
y=vsinrt-0.5gt
1=usin35*5.74-0.5*10*5.74*5.74
u=50.61m/s
b.horizontal distance traveled by ball
distance/time=velocity
then
distance/time=ucosr
distance=50cos35*5.74
distance=235m
c.Time of the ball in air.
t=2usinr/g
time=?
unitial velocity=50m/s
gravity=10
time= 2*50*sin35/10=5.74s
Any idea about this question?