- #1
KingKai
- 34
- 0
The equation
v22 = vo2 + 2aΔy
is used to determine the change in position, acceleration, or velocity of a particle under the influence of a quadratic force.
on earth, the acceleration value in this equation would, under normal circumstances, be
a= -9.8 m/s2.
so, this substitutes into
v22 = vo2 + -19.6Δy
In this
Δy = v22 - vo2 / -19.6
Lets now assume that v22 is 0, the crest of a projectiles motion.
Δy = 0 - vo2 / -19.6
If the objects initial v is facing upwards, then obviously the net Δy would be positive.
Now, keeping all conditions the same, let's assume that the acceleration is 9.8m/ss upwards
This would yield
Δy = 0 - vo2 / 19.6
Δy would thus be negative, and the object would be thrown downwards, accelerating upwards.
v22 = vo2 + 2aΔy
is used to determine the change in position, acceleration, or velocity of a particle under the influence of a quadratic force.
on earth, the acceleration value in this equation would, under normal circumstances, be
a= -9.8 m/s2.
so, this substitutes into
v22 = vo2 + -19.6Δy
In this
Δy = v22 - vo2 / -19.6
Lets now assume that v22 is 0, the crest of a projectiles motion.
Δy = 0 - vo2 / -19.6
If the objects initial v is facing upwards, then obviously the net Δy would be positive.
Now, keeping all conditions the same, let's assume that the acceleration is 9.8m/ss upwards
This would yield
Δy = 0 - vo2 / 19.6
Δy would thus be negative, and the object would be thrown downwards, accelerating upwards.