- #1
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im not use to working is 3D so i need some help
you are going to a restaurant. you leave your apartement and take the elevator 30 m down, then 15 m south to the exit. then u travel 200 m east and then 100 m to the restaurant. what is your displacement.
so what i did is:
-30k
-15j
+200i
+100j
then after adding them up:
[tex]\Delta d=\sqrt{200i^2+85j^2+(-30k^2)}[/tex]
displacement = ~ 219.37 m
is this right? and how do i represent the final direction?
thanks
you are going to a restaurant. you leave your apartement and take the elevator 30 m down, then 15 m south to the exit. then u travel 200 m east and then 100 m to the restaurant. what is your displacement.
so what i did is:
-30k
-15j
+200i
+100j
then after adding them up:
[tex]\Delta d=\sqrt{200i^2+85j^2+(-30k^2)}[/tex]
displacement = ~ 219.37 m
is this right? and how do i represent the final direction?
thanks