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The definition of Δ (difference,drop of) Electrostatic Potential Energy (D E-PE) says it
'is the work done on a unit charge (e) to bring it from r to r1 (against the force) with constant (without acceleration) velocity and extremely low absolute value of velocity (quasistatic, vanishingly small, etc..)
afaik, v must be steady not to create magnetic disturbances or the like.
It escapes me what would happen if value of v is , say, 1 cm/s. (constant)
(We can shoot an electron in a G Field at 1 Km/ s without problems, and get exact D G-PE)
Could you explain this to me, possibly without formulas? I need only to grasp the general idea!
Thanks
(* to simplify discussion let's assume the following ideal conditions:
A positive charge in vacuum distant from Galaxies equivalent of GM ( 0.0000184 C ?)at the origin r(o) and
one electron (e) at r = r(earth) = 6.4x 10^6 m moving to r1 at v= 1 cm (m, km?)/ s)
'is the work done on a unit charge (e) to bring it from r to r1 (against the force) with constant (without acceleration) velocity and extremely low absolute value of velocity (quasistatic, vanishingly small, etc..)
afaik, v must be steady not to create magnetic disturbances or the like.
It escapes me what would happen if value of v is , say, 1 cm/s. (constant)
(We can shoot an electron in a G Field at 1 Km/ s without problems, and get exact D G-PE)
Could you explain this to me, possibly without formulas? I need only to grasp the general idea!
Thanks
(* to simplify discussion let's assume the following ideal conditions:
A positive charge in vacuum distant from Galaxies equivalent of GM ( 0.0000184 C ?)at the origin r(o) and
one electron (e) at r = r(earth) = 6.4x 10^6 m moving to r1 at v= 1 cm (m, km?)/ s)
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