- #1
ryan8888
- 26
- 0
Hi all,
I am trying to work out the following:
cos2(t)sin(t)y' = -cos3(t)y + 1
I've moved put the equation into the standard form and determined that my integrating factor is the integral of cos(t)/sin(t) or the integral of cot(t). This gives me elnsinu +c or sin(t).
I multiple both sides and simplify and I get to this point"
y*sin(t) = Integral of: 1/cos2(t) and I'm having a hard time finding the integral of this function.
Once I solve the integral on the right hand side I'm home free but can't figure it out.
Any help is appreciated.
Thanks
Ryan
I am trying to work out the following:
cos2(t)sin(t)y' = -cos3(t)y + 1
I've moved put the equation into the standard form and determined that my integrating factor is the integral of cos(t)/sin(t) or the integral of cot(t). This gives me elnsinu +c or sin(t).
I multiple both sides and simplify and I get to this point"
y*sin(t) = Integral of: 1/cos2(t) and I'm having a hard time finding the integral of this function.
Once I solve the integral on the right hand side I'm home free but can't figure it out.
Any help is appreciated.
Thanks
Ryan