- #1
cAn
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Ok well here goes.
what is teh chance of flipping a coin 10 times and getting either 10 heads or 10 tails. Once this is known, how many times would you expect to flip a coin before you get 10 in a row(I of course don't mean that after this number you would be guaranteed to get 10 in a row, i just mean statistically).
here is what I'm thinking:
the chance of flipping a coin 10 times and getting all heads or all tails would be 1 in 2^9. Since the first of the 10 flips doesn't really matter so it is only the remaining 9 that count.
so you have a 1 in 512 chance that you will flip 10 of the same in a row.
Now, to figure out how to how many flips it should take to get this result, i used the idea that you would need 512 groups of 10 flips to achieve this.
to get 512 groups of 10 i would think that it would take 521 flips to achieve this, since:
11flips is essentially 2 chances at a group of 10(1-10, 2-11)
12 is 3 chances
13 is 4 chances
14 is 5 chances
.
.
.
521 is 512 chances.
Am I right in my logic?
what is teh chance of flipping a coin 10 times and getting either 10 heads or 10 tails. Once this is known, how many times would you expect to flip a coin before you get 10 in a row(I of course don't mean that after this number you would be guaranteed to get 10 in a row, i just mean statistically).
here is what I'm thinking:
the chance of flipping a coin 10 times and getting all heads or all tails would be 1 in 2^9. Since the first of the 10 flips doesn't really matter so it is only the remaining 9 that count.
so you have a 1 in 512 chance that you will flip 10 of the same in a row.
Now, to figure out how to how many flips it should take to get this result, i used the idea that you would need 512 groups of 10 flips to achieve this.
to get 512 groups of 10 i would think that it would take 521 flips to achieve this, since:
11flips is essentially 2 chances at a group of 10(1-10, 2-11)
12 is 3 chances
13 is 4 chances
14 is 5 chances
.
.
.
521 is 512 chances.
Am I right in my logic?