- #36
dipole
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- 151
Trifis said:It is good to know that the are some people willing to let us know what we already know...
BUT the primary question remains emphatically unanswered, so may I state it again:
D=ε[itex]_{0}[/itex]E+P , ∇D=ρ[itex]_{free}[/itex]
H=B/μ[itex]_{0}[/itex]-Μ , ∇H=j[itex]_{free}[/itex]
There is an obvious asymmetry here... To my eyes at least!
That's your question, not the OP's. I think the short answer is that the H field is a just a mathematical tool, and shouldn't be thought of too literally. In CGS units they have the same units, the fact that they have different units in SI is one of the shortcomings of that rather outdated system. Most advanced and newer E&M textbooks use CGS.