- #1
maca_404
- 7
- 0
Question is a golf ball is dropped from a height of 78m assuming gravity is 9.8 m s, What is the velocity of the ball after the first 10m.
I assume the equation to use is [tex]v^2=u^2+2ax[/tex]
v = Final velocity
u = Initial Velocity
a = Acceleration
x = Displacement
So I plug in [tex]v^2 = 0+2(9.8ms)(10.0)[/tex]
Now according to the answer sheet V should be 14.0 m s but no matter how I plug this in I can't seem to get the right answer.
I think the problem is the way I am actually doing the math so if someone could perhaps step threw the maths so I can see where I went wrong.
Thanks for any help
I assume the equation to use is [tex]v^2=u^2+2ax[/tex]
v = Final velocity
u = Initial Velocity
a = Acceleration
x = Displacement
So I plug in [tex]v^2 = 0+2(9.8ms)(10.0)[/tex]
Now according to the answer sheet V should be 14.0 m s but no matter how I plug this in I can't seem to get the right answer.
I think the problem is the way I am actually doing the math so if someone could perhaps step threw the maths so I can see where I went wrong.
Thanks for any help