- #1
Prometheos
- 13
- 0
This question was on my test I have no idea how to do the middle work.
Find the length of the curve
[tex] y = \frac{1}{2}(e^x + e^{-x}) , 0 \leq x \leq 2 [/tex]
Problem set up was easy enough
[tex] L= \int_0^2 \sqrt{ 1 + \frac{1}{4}( e^{2x} -2 + e^{-2x} ) } dx [/tex]
Looking back in my notes I see that the answer is
[tex] \frac{1}{2}( e^2 - e^{-2} ) [/tex]
But, how do you get there? I think my main problem is probably the algebra behind combing the 1 and derivative of y squared.
Find the length of the curve
[tex] y = \frac{1}{2}(e^x + e^{-x}) , 0 \leq x \leq 2 [/tex]
Problem set up was easy enough
[tex] L= \int_0^2 \sqrt{ 1 + \frac{1}{4}( e^{2x} -2 + e^{-2x} ) } dx [/tex]
Looking back in my notes I see that the answer is
[tex] \frac{1}{2}( e^2 - e^{-2} ) [/tex]
But, how do you get there? I think my main problem is probably the algebra behind combing the 1 and derivative of y squared.