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flemonster
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Homework Statement
Calculate new freezing point and boiling point when 0.47 mol ethylene glycol and 0.14 mol KBr is added to 150g H2O. Express your answer using one decimal place.
Homework Equations
molality = moles solute/kg solvent
ΔTf=i*Kf*m
ΔTb=i*Kb*m
New bp = ΔTb + normal bp
New fp = normal fp -ΔTf
ΔTf = change in freezing point
ΔTb = change in boiling point
m = molality of solution
Kb = boiling point constant
Kf = freezing point constant
i = number of solute particles
The Attempt at a Solution
Molality of solution = (0.14 mol KBr +0.47 mol ethylene glycol)/(0.150 kg H2O) = 4.1 m
Kf H2O = 1.86°C/m (from table provided in the problem)
i = 3 (ethylene glycol is a covalently bonded molecule but potassium bromide dissociates into its constituent ions)
ΔTf = 3*1.86*4.1 = 22.9
New fp = 0 - 22.9 = -22.9°C
Kb H2O = 0.51°C/m (from table provided in the problem)
ΔTb = 3*0.51*4.1 = 6.3
New bp = 100 + 6.3 = 106.3°C
EDIT: I put the bp into mastering chemistry and it told me that I might have used the wrong number of sig figs or have committed a rounding error. I have no idea what I am doing wrong because I have checked and double checked the calculations. I also put in 106.2 into the answer box and it said the same thing about rounding and sig figs. I'm hesitant to try the fp as I have already been marked down. Any help?
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