- #1
iceT
- 8
- 0
Blood can carry excess energy from the interior to the surface of the body, where the energy is dispersed in a number of ways. While a person is exercising, 0.8 kg of blood flows to the surface of the body and releases 2050 J of energy. The blood arriving at the surface has the temperature of the body interior, 37.0°C. Assuming that blood has the same specific heat capacity as water, determine the temperature of the blood that leaves the surface and returns to the interior
ok..I know that DELTA T = Q/cm
Q= heat
since i don't have the heat..i had to find it...so i did this
Q=( CM ) ( DELTA T ) = ( 4186 ) ( .8 ) ( 37.0 °C - 15.0 °C )
= 73673.6 J
now I got the heat...so i can apply this formula to find the temperature..
DELTA T = Q/cm = 73673.6 / ( 4186 ) ( .8 ) = 22 °C
but still..i keep getting it wrong... ..does anyone knows what I am doing wrong ??..
ok..I know that DELTA T = Q/cm
Q= heat
since i don't have the heat..i had to find it...so i did this
Q=( CM ) ( DELTA T ) = ( 4186 ) ( .8 ) ( 37.0 °C - 15.0 °C )
= 73673.6 J
now I got the heat...so i can apply this formula to find the temperature..
DELTA T = Q/cm = 73673.6 / ( 4186 ) ( .8 ) = 22 °C
but still..i keep getting it wrong... ..does anyone knows what I am doing wrong ??..
Last edited: