- #1
kq6up
- 368
- 13
I was reading in my textbook that the scalar product of two complex vectors is also complex (I assuming this is true in general, but not in every case). However for the general definition (the inner product), each element of one of the vectors needs to be its complex conjugate. I learned this in Mary Boas' methods. If this is the case, shouldn't all the imaginary component get zapped, and leave a scalar in ##\mathbb{R}##.
Chris
Chris