- #1
elitespart
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1. y=sec[tex]^{2}x[/tex] and y=e[tex]^{2x}[/tex], in Quadrant I, for x[tex]\leq[/tex]1. I need to calculate the area.
2. fundamental theorem
3. I'm using 0 and 1 as my lower and upper bounds and the answer I'm getting is -1.637 which is not reasonable. When I integrate using the calculator it's coming out to be 1.557. Where am I going wrong? Here's my work: (tan(1)-e[tex]^{2}[/tex]/2) - (tan(o) - e[tex]^{0}[/tex]/2)
Thanks.
2. fundamental theorem
3. I'm using 0 and 1 as my lower and upper bounds and the answer I'm getting is -1.637 which is not reasonable. When I integrate using the calculator it's coming out to be 1.557. Where am I going wrong? Here's my work: (tan(1)-e[tex]^{2}[/tex]/2) - (tan(o) - e[tex]^{0}[/tex]/2)
Thanks.