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Accelerating reference frame 
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#1
May513, 09:14 AM

P: 25

I'm attempting to build a line follower robot and I'm currently in the process of building appropriate models.
For the control system I need to define a coordinate system. The most convinient coordinate system from many point of views would be a coordinate system that moves along and changes direction with the robot, thus a rotating and accelerating reference frame. The question is if calculations regarding acceleration still would be valid if they are carried out in the same way as in a fixed reference frame. The calculations to be carried out are: ƩM = Jω'  Angular acceleration related to net torque applied ƩF = ma  Acceleration of center of gravity related to net force applied I've glanced some about information regarding the coriolis effect but I dont really understand it yet. No "loose" object are to be treated in the reference frame. 


#2
May513, 12:40 PM

P: 3,932

You need to include inertial forces:
http://en.wikipedia.org/wiki/Fictiti...titious_forces 


#3
May613, 02:22 PM

P: 25

Aha. That was an interesting article.
The force observed from an arbitrary accelerating and rotating coordinatesystem is Fb= Fa + F[itex]_{fic}[/itex] F[itex]_{fic}[/itex] = (m[itex]_{ab}[/itex] + 2mƩv[itex]_{j}[/itex]u'[itex]_{j}[/itex] + mƩx[itex]_{j}[/itex]u´´[itex]_{j}[/itex]) Fb is the appearent force that an observer in a rotating reference frame would think is acting on an object, while F is the "real" force an observer in an inertial reference frame would see and Ffic is the fictional force coming from the movements of the ref. system and m[itex]_{ab}[/itex] is the acceleration of the ref. system. I however want a coordinatsystem that is fixed both in position and angle to the robot at a point on the robot which defines position [0,0,0]. The position and velocity in its "own" coordinatesystem would thus be 0. Will this zero all terms in the Ffic and leave Fb = F  m[itex]_{ab}[/itex] in this particular case? As the robot would see the acceleration and in combination the force "on itself" in this system as zero we would get back F = m[itex]_{ab}[/itex] if the world of math smiles to me this time? 


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