# Accelerating reference frame

by MechatronO
Tags: accelerating, frame, reference
 P: 25 Aha. That was an interesting article. The force observed from an arbitrary accelerating and rotating coordinatesystem is Fb= Fa + F$_{fic}$ F$_{fic}$ = -(m$_{ab}$ + 2mƩv$_{j}$u'$_{j}$ + mƩx$_{j}$u´´$_{j}$) Fb is the appearent force that an observer in a rotating reference frame would think is acting on an object, while F is the "real" force an observer in an inertial reference frame would see and Ffic is the fictional force coming from the movements of the ref. system and m$_{ab}$ is the acceleration of the ref. system. I however want a coordinatsystem that is fixed both in position and angle to the robot at a point on the robot which defines position [0,0,0]. The position and velocity in its "own" coordinatesystem would thus be 0. Will this zero all terms in the Ffic and leave Fb = F - m$_{ab}$ in this particular case? As the robot would see the acceleration and in combination the force "on itself" in this system as zero we would get back F = m$_{ab}$ if the world of math smiles to me this time?