- #1
Amith2006
- 427
- 2
Sir,
Please help me with this problem.
# A fixed mass of gas at constant pressure occupies a volume V. The gas undergoes a rise in temperature so that the root mean squared velocity(c) of the molecule is doubled. What is the new volume?
I solved it in the following way:-
Let V1 be the initial volume & V2 be the final volume. Assuming the pressure to be constant,
c = (3PV1/M)^1/2 --------- (1)
2c = (3PV2/M)^1/2 --------- (2)
Dividing equation (1) by (2) we get,
½ = (V1/V2)^1/2
Squaring on both sides we get,
¼ = (V1/V2)
V2 = 4V1
But the answer given in my book is V2 = V1/[(2)^1/2] read as V1 divided by root 2.Here the symbol ^ represents power.
Please help me with this problem.
# A fixed mass of gas at constant pressure occupies a volume V. The gas undergoes a rise in temperature so that the root mean squared velocity(c) of the molecule is doubled. What is the new volume?
I solved it in the following way:-
Let V1 be the initial volume & V2 be the final volume. Assuming the pressure to be constant,
c = (3PV1/M)^1/2 --------- (1)
2c = (3PV2/M)^1/2 --------- (2)
Dividing equation (1) by (2) we get,
½ = (V1/V2)^1/2
Squaring on both sides we get,
¼ = (V1/V2)
V2 = 4V1
But the answer given in my book is V2 = V1/[(2)^1/2] read as V1 divided by root 2.Here the symbol ^ represents power.