- #1
JavaJoeUK2011
- 6
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1. Helo all,
A horizontal force of 80N acts on a mass of Kg resting on a horizontal surface. The mass is initially at rest and covers a distance of 5m in 0.92s under the action of the force. Assuming there are no energy losses due to air resistance and therefore that the acceleration is constant
2. F=ma v=s/t P=Fv
3. F=80, m=6, a=13.33,
v= 5 / 0.92 = 5.4347
P = 80 x 5.4347 = 434.776
Does this give me the total energy expended?
Thanks in advance
A horizontal force of 80N acts on a mass of Kg resting on a horizontal surface. The mass is initially at rest and covers a distance of 5m in 0.92s under the action of the force. Assuming there are no energy losses due to air resistance and therefore that the acceleration is constant
2. F=ma v=s/t P=Fv
3. F=80, m=6, a=13.33,
v= 5 / 0.92 = 5.4347
P = 80 x 5.4347 = 434.776
Does this give me the total energy expended?
Thanks in advance