- #1
thenewbosco
- 187
- 0
I am supposed to find an approximation of this integral evaluated between the limits 0 and 1 using a taylor expansion for cos x:
[tex]\int \frac{1 - cos x}{x}dx[/tex]
and given
[tex]cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{6!}...[/tex]
i should get a simple series similar to this for [tex]\frac{1 - cos x}{x}[/tex] and be able to simply integrate each term of the series and evaluate the integral for an approx. how do i find this series?
[tex]\int \frac{1 - cos x}{x}dx[/tex]
and given
[tex]cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{6!}...[/tex]
i should get a simple series similar to this for [tex]\frac{1 - cos x}{x}[/tex] and be able to simply integrate each term of the series and evaluate the integral for an approx. how do i find this series?