- #1
boboYO
- 106
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Homework Statement
http://img8.imageshack.us/img8/2393/geartain.jpg
The Attempt at a Solution
I got the right answer, by assuming that [tex]\omega_3=\omega_6[/tex] , but i don't know why this has to be so.
Here's my working:[tex]
\frac{\omega_2-\omega_3}{\omega_4-\omega_3}=-\frac{N_4}{N_2}[/tex]
[tex]
\frac{\omega_6-\omega_7}{\omega_4-\omega_7}=-\frac{N_4}{N_6}[/tex]Then, subbing in [tex]\omega_4 = 0[/tex] and [tex]N_6=N_2[/tex], equating the above 2 equations, and rearranging, I end up with
[tex]\frac{\omega_2}{\omega_7}=\left(1+\frac{N_4}{N_2}\right)^2\frac{w_3}{w_6}[/tex]
which gives the right answer, 68.0625, if i let [tex]\frac{w_3}{w_6}=1[/tex]
but why?
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