- #1
vorcil
- 398
- 0
A Carnot heat engine uses a hot reservoir consisting of a large amount of boiling water and a cold reservoir consisting of a large tub of ice and water.
In 5 minutes of operation of the engine, the heat rejected by the engine melts a mass of ice equal to 2.85×10−2 Kg.
Throughout this problem use Lf=3.34*10^5 j/kg for the heat of fusion for water.
- During this time, how much work is performed by the engine?
my attempt:
i noticed that the two temperature differences are 100 degrees and 0 degrees(mixture of icenwater)
so the maximum efficiency is n = 1- qc/qh = 0.27
how much work is performed by the engine,
Q(work)=Mass melted * latent heat fusion thing
Qc= m*Lf
so (2.85*10^-2 ) * (3.34*10^5) = 9519 Joules
now this is where my question comes in,
do i multiply the efficiency, 0.27 by 9519
to get the work performed by the engine
or is that the work lost by the engine so 9519-.27*9519
i just wanted to check before i submit the awnser(it's mastering physics)
In 5 minutes of operation of the engine, the heat rejected by the engine melts a mass of ice equal to 2.85×10−2 Kg.
Throughout this problem use Lf=3.34*10^5 j/kg for the heat of fusion for water.
- During this time, how much work is performed by the engine?
my attempt:
i noticed that the two temperature differences are 100 degrees and 0 degrees(mixture of icenwater)
so the maximum efficiency is n = 1- qc/qh = 0.27
how much work is performed by the engine,
Q(work)=Mass melted * latent heat fusion thing
Qc= m*Lf
so (2.85*10^-2 ) * (3.34*10^5) = 9519 Joules
now this is where my question comes in,
do i multiply the efficiency, 0.27 by 9519
to get the work performed by the engine
or is that the work lost by the engine so 9519-.27*9519
i just wanted to check before i submit the awnser(it's mastering physics)
Last edited: