Finding the Nth Root of a Number without a Calculator

In summary, there is a pencil and paper method to find the nth root of a number by using Newton's method. This method involves making an initial guess and then improving it using a formula that converges quickly to the correct answer. It can also be used to perform divisions quickly.
  • #1
Holocene
237
0
Is there any "pencil and paper" method to find the nth root of a number?

Since multiplying a number by itself any number of times quickly yeilds extremely large numbers, trial and error might seem to pinpoint the root of a number, so long as it is a perfect square or cube or whatever.

But, is there any real way to pinpoint the root of a number without using a calculator or trial and error?
 
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  • #2
To compute the nth root of a number Y, just make some guess X and then improve that guess using the formula:

[tex]\left(1-\frac{1}{n}\right)X + \frac{Y}{n X^{n-1}}[/tex]

You can iterate this to make further improvements. E.g. suppose you want to estimate the cube root of 10. Then you can take X = 2. the formula gives: 4/3 + 10/(3*4) = 2 + 1/6

If you then take X = 2+1/6 and insert that in the formula to get 2.1545. Iterating again gives 2.15443469224. Now, believe it or not but:

2.15443469224^3 = 10.0000000307 :smile:
 
  • #3
If you want to know the general theory behind the above method, see http://planetmath.org/encyclopedia/NewtonsMethod.html .
 
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  • #4
So, this is still trial and error, but it converges very fast. At each step you double to correct number of digits. You go from a wild guess to a number that is correct to ten significant digits in about four iterations.
 
  • #5
Count Iblis said:
To compute the nth root of a number Y, just make some guess X and then improve that guess using the formula:

[tex]\left(1-\frac{1}{n}\right)X + \frac{Y}{n X^{n-1}}[/tex]

You can iterate this to make further improvements. E.g. suppose you want to estimate the cube root of 10. Then you can take X = 2. the formula gives: 4/3 + 10/(3*4) = 2 + 1/6

If you then take X = 2+1/6 and insert that in the formula to get 2.1545. Iterating again gives 2.15443469224. Now, believe it or not but:

2.15443469224^3 = 10.0000000307 :smile:

wow, that's pretty neat. Thanks!
 
  • #6
The case n = -1 is also very useful. In that case X = 1/Y but Newton's method gives:

[tex]2X - X^{2} Y[/tex]

Since there are no divisions in here, you can use it to do divisions. It's much faster than long division.
 

1. How do I find the Nth root of a number without using a calculator?

Finding the Nth root of a number without a calculator involves using mathematical techniques such as prime factorization, logarithms, or estimation. The specific method will depend on the number and the value of N.

2. What is the process for finding the Nth root of a number using prime factorization?

To find the Nth root of a number using prime factorization, you need to break down the number into its prime factors and then group them in sets of N. The Nth root will be the product of the prime factors in one of these groups.

3. Can logarithms be used to find Nth roots of numbers?

Yes, logarithms can be used to find Nth roots of numbers. The formula for finding the Nth root of a number using logarithms is Nth root = log(base N) (number). This method is helpful for finding roots of large numbers or numbers with many digits.

4. How can I estimate the Nth root of a number without a calculator?

One way to estimate the Nth root of a number without a calculator is to use the "guess and check" method. Start with a guess for the root and then adjust it until you get closer to the actual root. Another method is to use the binomial theorem, which involves expanding a binomial expression to approximate the root.

5. Are there any shortcuts or tricks for finding Nth roots without a calculator?

There are a few shortcuts or tricks that can be used to find Nth roots without a calculator. For example, if the number is a perfect square, the square root will be a whole number. Additionally, knowing basic multiplication and division facts can help with estimation and finding roots of smaller numbers.

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