- #1
Bob19
- 71
- 0
Hi
I have a question regarding the use of de moivre formula:
I'm presented with a complex number [tex] z = (cos(v) + i sin(v))^n = 1[/tex]
I'm suppose to show that [tex]z^n = 1[/tex] is a root of unity. Is there a procedure on how to show this? If n = 6 and [tex]v = \frac{4 \pi}{6}[/tex]
Sincerely and Best Regards
Bob
I have a question regarding the use of de moivre formula:
I'm presented with a complex number [tex] z = (cos(v) + i sin(v))^n = 1[/tex]
I'm suppose to show that [tex]z^n = 1[/tex] is a root of unity. Is there a procedure on how to show this? If n = 6 and [tex]v = \frac{4 \pi}{6}[/tex]
Sincerely and Best Regards
Bob