- #1
Maroc
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Homework Statement
6x^2 - 4
x = -2
Homework Equations
n/a
The Attempt at a Solution
I input -2 for x but i got the wrong answer..the answer is suppose to be -24
Bohrok said:You'll need to use the difference quotient
[tex]\frac{f(x + h) - f(x)}{h}[/tex]
Do you know why and how to use it for the problem?
Bohrok said:You'll need to use the difference quotient
[tex]\frac{f(x + h) - f(x)}{h}[/tex]
Do you know why and how to use it for the problem?
The easier way that I know is that you have to find the derivative of f(x) = 6x^2 - 4.Maroc said:Homework Statement
6x^2 - 4
x = -2Homework Equations
n/aThe Attempt at a Solution
I input -2 for x but i got the wrong answer..the answer is suppose to be -24
Instantaneous rate of change is the rate at which a quantity changes at a specific point in time. It measures the exact rate of change at a single moment, rather than an average rate of change over an interval of time.
To calculate instantaneous rate of change, you need to find the derivative of the function at a specific point. This can be done using calculus by taking the limit of the average rate of change as the interval approaches 0.
Instantaneous rate of change is important because it allows us to analyze how a quantity is changing at a specific moment. This is useful in many fields of science, such as physics, chemistry, and economics, to understand the behavior of various processes and systems.
The average rate of change measures the overall rate of change over an interval of time, while instantaneous rate of change measures the precise rate of change at a single moment. Average rate of change can be thought of as the slope of a line connecting two points on a graph, while instantaneous rate of change is the slope of the curve at a specific point.
Yes, instantaneous rate of change can be negative. This means that the quantity is decreasing at that specific moment in time. It is also possible for the instantaneous rate of change to be 0, indicating that the quantity is not changing at that point.