- #1
soandos
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so i understand how to resolve a limit at x->oo, but from a conceptual standpoint, i do not get it. for example,
limit x->oo, 4x/5x
so the answer is 4/5, but oo/oo is an indeterminate expression
i understand that if i treat x as a variable, then it makes sense, but still
if the example was 4x/5x and i said that x was infinity, then there would be no answer.
in addition
4*oo = 5*oo = oo
so following that method, it would return one as the answer every time there were the same exponents on the x (so in other words, a*x/(b*x)
can someone please explain this to me?
thanks.
limit x->oo, 4x/5x
so the answer is 4/5, but oo/oo is an indeterminate expression
i understand that if i treat x as a variable, then it makes sense, but still
if the example was 4x/5x and i said that x was infinity, then there would be no answer.
in addition
4*oo = 5*oo = oo
so following that method, it would return one as the answer every time there were the same exponents on the x (so in other words, a*x/(b*x)
can someone please explain this to me?
thanks.