- #1
- 996
- 5
My vector calculus is a bit rusty. Can anyone tell me if the following uses proper symbolism?
[tex]
F &= \left[\begin{matrix}f_1(x_1,x_2) \\ f_2(x_1,x_2) \\ f_3(x_1,x_2) \end{matrix}\right]
\qquad x = \left[\begin{matrix} x_1 \\ x_2 \end{matrix}\right]
\qquad \frac{DF}{dx}&=
\left[\begin{matrix}
\rule{0pt}{3ex}\frac{\partial f_1}{\partial x_1} & \frac{\partial f_1}{\partial x_2} \\
\rule{0pt}{3ex}\frac{\partial f_2}{\partial x_1} & \frac{\partial f_2}{\partial x_2} \\
\rule{0pt}{3ex}\frac{\partial f_3}{\partial x_1} & \frac{\partial f_3}{\partial x_2}\end{matrix}\right]
[/tex]
[tex]
F &= \left[\begin{matrix}f_1(x_1,x_2) \\ f_2(x_1,x_2) \\ f_3(x_1,x_2) \end{matrix}\right]
\qquad x = \left[\begin{matrix} x_1 \\ x_2 \end{matrix}\right]
\qquad \frac{DF}{dx}&=
\left[\begin{matrix}
\rule{0pt}{3ex}\frac{\partial f_1}{\partial x_1} & \frac{\partial f_1}{\partial x_2} \\
\rule{0pt}{3ex}\frac{\partial f_2}{\partial x_1} & \frac{\partial f_2}{\partial x_2} \\
\rule{0pt}{3ex}\frac{\partial f_3}{\partial x_1} & \frac{\partial f_3}{\partial x_2}\end{matrix}\right]
[/tex]
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