- #1
Delber
- 19
- 0
I'm having trouble with this problem. I can't seem to wrap my head around it and any help would be appreciated.
The problem is:
A stone falls from the top of the cliff. One second later, another falls from a ledge 45m below the top. The two stones hit the bottom simultaneously. Find the time taken for the first stone to fall and the height of the cliff.
x = ut+ 1/2at^2 where x is distance and u is initial velocity
I tried a couple attempts at the problem. I began by trying to make two equations equal together, but I ran into the problem that the time and distance traveled is not equal so I tried to make a system of equations. I can't figure out how to make a suitable system where I can easily solve for one variable.
Homework Statement
The problem is:
A stone falls from the top of the cliff. One second later, another falls from a ledge 45m below the top. The two stones hit the bottom simultaneously. Find the time taken for the first stone to fall and the height of the cliff.
Homework Equations
x = ut+ 1/2at^2 where x is distance and u is initial velocity
The Attempt at a Solution
I tried a couple attempts at the problem. I began by trying to make two equations equal together, but I ran into the problem that the time and distance traveled is not equal so I tried to make a system of equations. I can't figure out how to make a suitable system where I can easily solve for one variable.