- #1
QuantumPixel
- 7
- 1
Use the chain rule to show that
dz/dx = (cos(theta) * dz/dr) - (1/r * sin(theta) dz/dtheta) and
dz/dy = (sin(theta) dz/dr) + 1/r * cos(theta) dz/dtheta)
where dz/dx, dz/dr, dz/dtheta, and dz/dy and first partial derivatives.
Saw this a textbook the other day and I did not understand it.
dz/dx = (cos(theta) * dz/dr) - (1/r * sin(theta) dz/dtheta) and
dz/dy = (sin(theta) dz/dr) + 1/r * cos(theta) dz/dtheta)
where dz/dx, dz/dr, dz/dtheta, and dz/dy and first partial derivatives.
Saw this a textbook the other day and I did not understand it.