- #1
huskydc
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During one hot summer, a physics grad student went to the local toy store and purchased a plastic child's swimming pool. Upon returning home, he filled it with 200 liters of water at 25 C. Realizing that the water would probably not be cool enough, he threw ice cubes from his refrigerator, each of mass 30g, into the pool. (The ice cubes were originally at 0C.) He continued to add ice cubes, until the temperature stabilized to 16C. He then got in the pool.
How many ice cubes did he add to the pool to get the temperature to 16 C? (Consider the pool and ice cubes an isolated system.)
ok..i tried doing the following:
heat lost by water= heat gained by ice cubes
Q water = m c delta T
from the fact d=m/v, i got mass of water as 200 kg
so Q water = 200 (4186) 9 = 7534800 J
then I'm not so sure as to where i go from here...
I've been told to find the heat gained by ice cubes including the melting...how should i do that?
How many ice cubes did he add to the pool to get the temperature to 16 C? (Consider the pool and ice cubes an isolated system.)
ok..i tried doing the following:
heat lost by water= heat gained by ice cubes
Q water = m c delta T
from the fact d=m/v, i got mass of water as 200 kg
so Q water = 200 (4186) 9 = 7534800 J
then I'm not so sure as to where i go from here...
I've been told to find the heat gained by ice cubes including the melting...how should i do that?