- #1
badtwistoffate
- 81
- 0
in int[6/(x^2+3)^2] i use 3tanU=x, dx=3sec(u)^2 du
using that i get to ... int[1+cos2u]= u + sin2u/2 = u +sin u cos u... but subing back in with trig doesn't give me the right answer... any help with this method?
using that i get to ... int[1+cos2u]= u + sin2u/2 = u +sin u cos u... but subing back in with trig doesn't give me the right answer... any help with this method?