- #1
Berkshire
- 3
- 0
Hello, I'm studying for a test and this is a question on a practice test...
cos(x)+y^2+(2yx-1)y'=0
I can't separate the variables (it's not homogeneous, either), this isn't exact and bernoulli won't work...
dy/dx=-cos(x)/(2yx-1)-y^2/(2yx-1)
I changed the equation so it would look like this but I can't simplify it any more than that and I can't just take the integral of it here...If anyone could give me some help with this problem it would be much appreciated. Thanks!
cos(x)+y^2+(2yx-1)y'=0
I can't separate the variables (it's not homogeneous, either), this isn't exact and bernoulli won't work...
dy/dx=-cos(x)/(2yx-1)-y^2/(2yx-1)
I changed the equation so it would look like this but I can't simplify it any more than that and I can't just take the integral of it here...If anyone could give me some help with this problem it would be much appreciated. Thanks!