- #1
chazgurl4life
- 52
- 0
Ok so my problem was: A 80 kg hiker starts at an elevation of 1600 m and climbs to the top of a 3600 m peak.
(a) What is the hiker's change in potential energy?
J
(b) What is the minimum work required of the hiker?
J
(c) Can the actual work done be more than this? YES!
so i figured out a) Change in PE = mg(y2-y1)
=80kg(9.8 m/s^2)(3600m-1600m)
= 1.56 x 10^6 Joules
B) Part b is the same answer cause with your PE you can perform minimum work
But for C i don't understand how the actual work be more than delta PE?
(a) What is the hiker's change in potential energy?
J
(b) What is the minimum work required of the hiker?
J
(c) Can the actual work done be more than this? YES!
so i figured out a) Change in PE = mg(y2-y1)
=80kg(9.8 m/s^2)(3600m-1600m)
= 1.56 x 10^6 Joules
B) Part b is the same answer cause with your PE you can perform minimum work
But for C i don't understand how the actual work be more than delta PE?