- #246
Ingvar Astrand
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Ingvar Astrand's answer to geistkiesel:
No redshift implies increasing wavelengths and decreasing frequencies.
The frequencies of the wave-units that the moving observer meet increase (he meets the wave-units faster) and he sees longer waves that appears shorter to him. So the light-spectrum he sees have - depending on his eyes' invariant frequency-reaction - longer wave-lengths in the reality (relative to the space or the observer in rest).
The complicated Doppler-formulas do hardly explain what really happens.
An observer that moves forwards relative to the radiation from a source have his eyes' optical (light) frequency spectrum invariant but the wavelengths appears as shorter to him [the eye's invariable frequency = (c+observer’s velocity)/wavelength]. The wavelengths of the light spectrum that appear as (is) normal for the moving observer's eyes are wavelengths that relative to the space in rest are longer.
The apparent wavelengths are the variable parameter that is changed proportionally with the observer's velocity depending on his eyes' inherent invariable light-frequency-reaction. If he travels at c+10% of c, the wave-units he sees (appears to him) as normal are the true wavelengths that are 10% longer. And the observer in rest sees the same wavelength’s spectrum as it is, proportional to his velocity that is 0 – that is: the laboratory-relation between frequencies and wavelengths
Let me refer to your example: First: frequency = velocity / wavelength
Let us calculate a specific yellow color of 6000 A (Angstrom) or 6 x 10^-7 m.
An observer in rest sees this yellow color's (laboratory-)frequency at (3 x 10^8m/s) / (6 x 10^-7 m/n) = 5 x 10^14 n/s (Hz)
Independent of his velocity this yellow color to him always has the frequency: 5 x 10^14 n/s (Hz).
If an observer moves at c+10% of c, his yellow color's wavelength is: (3.3 x 10^8m/s) / (5 x 10^14 n/s) = 6.6 x 10^-7 m (6600 A).
My derivation of the real theory of relativity is: symmetric, understandable, calculateable, and no crazy dilation of space or time. Now you need neither Lorentz' unintelligible equation nor Doppler's hardly explainable formulation.
I have presented my wholw "unified theory of physics" with this transition calculation (translation formulation) in proceedings at conferences in Kazan State University in Russia 2003, and with NPA and AAAS in Denver 2004.
In August you can read my whole theory at: http://www.theuniphysics.info
But till then, take a look at my Denver-abstracts and see the great range of the unified theory of physics.
geistkiesel said:Does it not seem more rational that the frequency will increase rather than the wavelength decrease? Red shift is an incease in the frequency in doppler measurements, not a shortening of wavelength.
No redshift implies increasing wavelengths and decreasing frequencies.
The frequencies of the wave-units that the moving observer meet increase (he meets the wave-units faster) and he sees longer waves that appears shorter to him. So the light-spectrum he sees have - depending on his eyes' invariant frequency-reaction - longer wave-lengths in the reality (relative to the space or the observer in rest).
The complicated Doppler-formulas do hardly explain what really happens.
An observer that moves forwards relative to the radiation from a source have his eyes' optical (light) frequency spectrum invariant but the wavelengths appears as shorter to him [the eye's invariable frequency = (c+observer’s velocity)/wavelength]. The wavelengths of the light spectrum that appear as (is) normal for the moving observer's eyes are wavelengths that relative to the space in rest are longer.
The apparent wavelengths are the variable parameter that is changed proportionally with the observer's velocity depending on his eyes' inherent invariable light-frequency-reaction. If he travels at c+10% of c, the wave-units he sees (appears to him) as normal are the true wavelengths that are 10% longer. And the observer in rest sees the same wavelength’s spectrum as it is, proportional to his velocity that is 0 – that is: the laboratory-relation between frequencies and wavelengths
Let me refer to your example: First: frequency = velocity / wavelength
Let us calculate a specific yellow color of 6000 A (Angstrom) or 6 x 10^-7 m.
An observer in rest sees this yellow color's (laboratory-)frequency at (3 x 10^8m/s) / (6 x 10^-7 m/n) = 5 x 10^14 n/s (Hz)
Independent of his velocity this yellow color to him always has the frequency: 5 x 10^14 n/s (Hz).
If an observer moves at c+10% of c, his yellow color's wavelength is: (3.3 x 10^8m/s) / (5 x 10^14 n/s) = 6.6 x 10^-7 m (6600 A).
My derivation of the real theory of relativity is: symmetric, understandable, calculateable, and no crazy dilation of space or time. Now you need neither Lorentz' unintelligible equation nor Doppler's hardly explainable formulation.
I have presented my wholw "unified theory of physics" with this transition calculation (translation formulation) in proceedings at conferences in Kazan State University in Russia 2003, and with NPA and AAAS in Denver 2004.
In August you can read my whole theory at: http://www.theuniphysics.info
But till then, take a look at my Denver-abstracts and see the great range of the unified theory of physics.