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tomrule007
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Homework Statement
A 200g puck sliding on ice strikes a barrier at an angle of 53degree and bounces off at an angle of 45degree. The speed of the puck before the bounce was 15m/s and after the bounce it is 12m/s. The time of contact during the bounce is .05seconds
A) write these velocities in rectangular components relative to the barrier
B) Determine the x and y components of the impulsive force. Which one can be identified as a normal force and which one can be identified as frictional force
Homework Equations
We were just introduced to impulse last class so i really don't know if I'm doing this right, but i wiki'ed it and see
Impulse = Change in Momentum
The Attempt at a Solution
A) Pretty sure i did this part right
Before:
V_x=15cos53 = 9.02723
V_y=15sin53 = 11.9795
After:
V_x=12cos45 = 8.48528
V_y=12sin45 = 8.48528B)This is were I'm kinda lost
Formula i used: I=M(v_i - V_f) (M=.2, v_i= velocity initial, v_f= velocity final)
I_x=.2(15cos53-12cos45)=.541944(.2) = .108389
I_y=.2(15sin53-12sin45)=3.49425(.2) = .69885
Guessing the I_y is caused from the normal force of the wall and the I_x is caused from friction.
Any help would be appreciated
-Thanks Tom
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