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MJC8719
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A bomber is flying horizontally over level terrain, with a speed of 265 m/s relative to the ground, at an altitude of 3200 m. Neglect the effects of air resistance.
(a) How far will a bomb travel horizontally between its release from the plane and its impact on the ground?
(b) At what angle from the vertical (less than 90°) should the telescopic bombsight be set so that the bomb will hit the target seen in the sight at the time of release?
Hey,
So this problem has been giving me a little trouble.
I believe I have solved for part A correctly:
vy^2 = -2g(change in y)
vy^2 = -2(-9.8)(3200)
vy = 250.4396
vy = -gt
250.4396 = 9.8t
t = 25.5551
horizontal distance = 25.5551 x 265 = 6772.10 m
I am really having trouble understanding what part B is asking for. If someone could put me in the right direction, I would really appreciate it.
Thanks
(a) How far will a bomb travel horizontally between its release from the plane and its impact on the ground?
(b) At what angle from the vertical (less than 90°) should the telescopic bombsight be set so that the bomb will hit the target seen in the sight at the time of release?
Hey,
So this problem has been giving me a little trouble.
I believe I have solved for part A correctly:
vy^2 = -2g(change in y)
vy^2 = -2(-9.8)(3200)
vy = 250.4396
vy = -gt
250.4396 = 9.8t
t = 25.5551
horizontal distance = 25.5551 x 265 = 6772.10 m
I am really having trouble understanding what part B is asking for. If someone could put me in the right direction, I would really appreciate it.
Thanks