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Benzoate
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Homework Statement
In order to take a nice warm bah, you mix 50 liters of hot water at 55 degrees celsuis wti h25 liters of cold water at 10 degrees celsius . how much new entropy have you created by mixing the water?
Homework Equations
Possible equations:
dS=Q/T:
Q=m*c*delta(T)
Q=m*L
The Attempt at a Solution
First, I need to convert the volumes of water into mass by multiplying the density of water by Volume.
m(hot)=(50 L)*(1.00 g/cm^3)= 50000 grams.
deltaS(hot)=(50000 g)*(4.18 J/(K*g))*(328 K-283 K)/(328 K)= 28673 J/K
m(cold)=(25 L)*(1.00 g/cm^3)= 25000 grams
deltaS(cold)=(25000 g)*(4.18 J/(K*g))*(283 K - 328 K)/(283 K)= -16616.60 J/K
deltaS(new)=deltaS(cold)+deltaS(hot)= (-16616.60 J/K)+(28273 J/K)= 11656.4 J/K