- #1
vkash
- 318
- 1
1 g mole of oxygen at 27 degree Celsius and 1 atmospheric pressure is enclosed in a vessel. The vessel is thermally insulated. This vessel is moving with speed of v0. Suddenly it is stopped. what will change in temperature of the gas.
How i did it.
first of all i find the root mean speed of the gas in position when there is no motion of vessel.
[tex]\sqrt[2]{\frac{3kT}{m}}[/tex]
after putting values it comes out to be 483.3 ms-1
(till here it is done similarly in book)
after this i apply this formula
[tex]\frac{T1}{T2}=(\frac{v1}{v2})^2[/tex]
Here v represent the root mean velocity of the gas molecules. I put T2=300,T1 is 301. v1=483.3 and v2=483.3+v'. v' is velocity of the container. I assume that when we suddenly stop the container. velocity v' became the velocity of gas molecules,
but after applying second formula i got answer around ~10ms-1 but answer is 36ms-1.
can you guys please point out my mistake.
How i did it.
first of all i find the root mean speed of the gas in position when there is no motion of vessel.
[tex]\sqrt[2]{\frac{3kT}{m}}[/tex]
after putting values it comes out to be 483.3 ms-1
(till here it is done similarly in book)
after this i apply this formula
[tex]\frac{T1}{T2}=(\frac{v1}{v2})^2[/tex]
Here v represent the root mean velocity of the gas molecules. I put T2=300,T1 is 301. v1=483.3 and v2=483.3+v'. v' is velocity of the container. I assume that when we suddenly stop the container. velocity v' became the velocity of gas molecules,
but after applying second formula i got answer around ~10ms-1 but answer is 36ms-1.
can you guys please point out my mistake.
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