Continuous Inelastic Collisions

In summary, the equation for the force function of displacement would be something like this: -kx-c\dot{x}
  • #1
mindoftea
6
0
Hi,
I am trying find equations for continuous "stretchy" collisions, in other words, I have two perfectly round objects of known mass, radius, and velocity, and want to collide them and be able to have them squish together and then bounce apart. I am aware of the method of solving for the intersections of momentum and KE equations, but I need collisions which take actual time, that method is instantaneous. So what I want is a force function of displacement which I can integrate and evaluate at a time t. So, something like this:
[itex]\int_{0}^{t}{f\left( x \right)\; dx}[/itex]
For f(x), I have been using Hooke's law of linear deformation--it works beautifully for elastic collisions. So [itex]f\left( x \right)=\frac{1}{\frac{1}{k1}+\frac{1}{k2}}[/itex], where k1 and k2 are the spring constants of the objects. Now, I want to expand this function for the general case: anywhere from inelastic to elastic depending on the objects. So what would f(x) be in that case? I'm sure that there are messy solutions involving pre-computing the time-length of the collision and then solving for percent loss based on that and percent elasticity, but what is the neatest, most generalizable integrand for this purpose? Hopefully one that just involves that instant's variables and no attempts to predict the future?
Thanks!
 
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  • #2
It seems to me that one could argue that the concept of a coefficient of restitution doesn't work here because if the percent loss is constant for a material, then, because the duration of the collision is variable depending on masses and velocities, the instantaneous energy loss would also have to be variable, which makes no sense.

So perhaps there is a constant instantaneous energy loss? Because there are infinite instants in the finite duration of the collision, perhaps this instantaneous energy loss would have to be infinitesimal? How would it fit into calculations?
 
  • #3
If you are using harmonic potential, use harmonic damping term for energy loss.

[tex]f(x)=-kx-c\dot{x}[/tex]
 
  • #4
Perfect! Thanks so much!
 
  • #5


I understand your desire to find a neat and generalizable solution for continuous inelastic collisions. However, the reality is that there is no one-size-fits-all equation for this type of collision. The behavior of two objects colliding and deforming is highly dependent on their specific properties such as shape, elasticity, and material composition.

One approach you can take is to use a more general form of Hooke's law, known as the generalized Hooke's law, which takes into account the non-linear behavior of materials under deformation. This equation is given by f(x) = kx + \frac{1}{2}k_2x^2 + \frac{1}{3}k_3x^3 + ..., where k, k2, k3, etc. are the different spring constants for each term. This equation can be used for both elastic and inelastic collisions, as it allows for different degrees of deformation depending on the objects' properties.

Another approach is to use a computer simulation to model the collision. By accurately representing the physical properties of the objects and using numerical integration methods, you can simulate the continuous collision and obtain the desired force function of displacement over time. This method allows for a more precise and customizable solution for your specific scenario.

In summary, while there is no one equation that can accurately describe all types of continuous inelastic collisions, you can use generalized Hooke's law or computer simulations to model and obtain the desired solution for your specific scenario. It is important to consider the unique properties of the objects involved and use appropriate equations and methods to accurately represent their behavior during the collision.
 

Related to Continuous Inelastic Collisions

1. What is a continuous inelastic collision?

A continuous inelastic collision is a type of collision in which two objects collide and stick together, resulting in a loss of kinetic energy. Unlike an elastic collision, the energy is not conserved and is instead converted into other forms, such as heat or sound.

2. What factors affect the outcome of a continuous inelastic collision?

The mass and velocity of the objects involved, as well as the angle and surface area of contact, can all affect the outcome of a continuous inelastic collision. These factors determine the amount of kinetic energy that is lost and the resulting motion of the objects after the collision.

3. How is the final velocity calculated in a continuous inelastic collision?

The final velocity in a continuous inelastic collision can be calculated using the equation v_final = (m1v1 + m2v2) / (m1 + m2), where m1 and m2 are the masses of the two objects and v1 and v2 are their initial velocities. This equation takes into account the conservation of momentum.

4. Can a continuous inelastic collision result in an increase in kinetic energy?

No, a continuous inelastic collision always results in a decrease in kinetic energy due to the conversion of energy into other forms. In an ideal scenario, where there is no external force or friction, the total kinetic energy before and after the collision will be the same, but the distribution of energy will change.

5. What are some real-world examples of continuous inelastic collisions?

Some examples of continuous inelastic collisions include car crashes, where the impact causes the vehicles to stick together and lose kinetic energy, and sports such as bowling or billiards, where the balls collide and stick together upon impact.

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