- #1
Geoff
- 10
- 0
Hello.
I need to calc the mechanical equivalent of heat.
I got a tube with some lead shot in it.
Tube is 1 m long. Lead shot is 11.3 kg.
It falls though 66 cm of the tube. (66 cm of the tube are empty).
It was fliped 100 times
temperature rose 10 degrees.
SO we get:
Q=11.3*130*10
where 130 is the specific heat of lead.
We got some number there.
That is heat.
Now we do:
Joules of mechanical energy=11.3*0.66*9.8*100(number of times flopped)
Now we get another number.
The two number need to be close to each other right? Or am i missing something when i am relating mechanical energy with heat?
the heat that was generated from Q=mcdeltat should equal the mgh#oftimesflipped, right?
Sry for the dumb post, but i don;t have a textbook on hand and i haven;t done this in a long while...
Thx
I need to calc the mechanical equivalent of heat.
I got a tube with some lead shot in it.
Tube is 1 m long. Lead shot is 11.3 kg.
It falls though 66 cm of the tube. (66 cm of the tube are empty).
It was fliped 100 times
temperature rose 10 degrees.
SO we get:
Q=11.3*130*10
where 130 is the specific heat of lead.
We got some number there.
That is heat.
Now we do:
Joules of mechanical energy=11.3*0.66*9.8*100(number of times flopped)
Now we get another number.
The two number need to be close to each other right? Or am i missing something when i am relating mechanical energy with heat?
the heat that was generated from Q=mcdeltat should equal the mgh#oftimesflipped, right?
Sry for the dumb post, but i don;t have a textbook on hand and i haven;t done this in a long while...
Thx
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