- #1
erik-the-red
- 89
- 1
Question
An object is a distance of 23.4 cm from the center of a silvered spherical glass Christmas tree ornament which has a diameter of 5.70 cm.
A What is the position of its image?
B What is the magnification of its image?
I think the object can be treated as a convex mirror.
s (object distance) = 23.4 cm
R = -(5.70)/2 = -2.85 cm
[tex]\frac{1}{s} + \frac{1}{s'} = \frac{2}{R}[/tex]
Using that equation, I get [tex]\frac{1}{s'} = \frac{2}{-2.85} - \frac{1}{23.4}[/tex].
Then, s' = -1.12 cm.
And, [tex]m = -\frac{s'}{s}[/tex], so m = .048.
I know for sure that -1.12 cm is not the correct answer, so most likely my second answer is also incorrect.
What did I do wrong?
An object is a distance of 23.4 cm from the center of a silvered spherical glass Christmas tree ornament which has a diameter of 5.70 cm.
A What is the position of its image?
B What is the magnification of its image?
I think the object can be treated as a convex mirror.
s (object distance) = 23.4 cm
R = -(5.70)/2 = -2.85 cm
[tex]\frac{1}{s} + \frac{1}{s'} = \frac{2}{R}[/tex]
Using that equation, I get [tex]\frac{1}{s'} = \frac{2}{-2.85} - \frac{1}{23.4}[/tex].
Then, s' = -1.12 cm.
And, [tex]m = -\frac{s'}{s}[/tex], so m = .048.
I know for sure that -1.12 cm is not the correct answer, so most likely my second answer is also incorrect.
What did I do wrong?