- #1
LogicalTime
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In the Tsiolkovsky rocket equation derivation there is a part that says:
[tex]\frac{dV}{dt} = -\upsilon_e \frac{1}{m} \frac{dm}{dt}[/tex]
"Assuming v_e, is constant, this may be integrated to yield:"
[tex]\Delta V\ = v_e \ln \frac {m_0} {m_1} [/tex]
How does this work? The differential is an operator and I am pretty sure you just can't cancel the dt. I wonder what assumptions are needed to be able to legally just remove the "dt"s though.
Thanks!
[tex]\frac{dV}{dt} = -\upsilon_e \frac{1}{m} \frac{dm}{dt}[/tex]
"Assuming v_e, is constant, this may be integrated to yield:"
[tex]\Delta V\ = v_e \ln \frac {m_0} {m_1} [/tex]
How does this work? The differential is an operator and I am pretty sure you just can't cancel the dt. I wonder what assumptions are needed to be able to legally just remove the "dt"s though.
Thanks!