- #1
zinedine_88
- 29
- 0
OK...
Please consider that picture in the following link
http://images.google.com/imgres?img...ages?q=moment+of+inertia&gbv=2&svnum=10&hl=en
It says that the DISK will reach the ground more quickly than the HOOP, since it has smaller moment of Inertia.! I GET THAT!
But what I cannot understand is, if that is true, how come when you calculate the kinetic energies of the DISK and the HOOP according to the formula KE=1/2mv^2,
that the kinetic energy of the disk is twice less than the kinetic energy of the HOOP.
put in a more simple words, HOW COME THE OBJECT THAT REACHES THE GROUND FIRST, HAS LESS KINETIC ENERGY than the slower object?
PLEASE EXPLAIN me!
Tony
Please consider that picture in the following link
http://images.google.com/imgres?img...ages?q=moment+of+inertia&gbv=2&svnum=10&hl=en
It says that the DISK will reach the ground more quickly than the HOOP, since it has smaller moment of Inertia.! I GET THAT!
But what I cannot understand is, if that is true, how come when you calculate the kinetic energies of the DISK and the HOOP according to the formula KE=1/2mv^2,
that the kinetic energy of the disk is twice less than the kinetic energy of the HOOP.
put in a more simple words, HOW COME THE OBJECT THAT REACHES THE GROUND FIRST, HAS LESS KINETIC ENERGY than the slower object?
PLEASE EXPLAIN me!
Tony