- #1
melissa_y
- 17
- 0
Indiana Jones!
My physics class had this problem for our homework set this week and nobody has figured it out. We asked for help from our TAs today and they didn't know how to help us either. If someone could look at this problem and tell me what they think I would really appreciate it.
Indiana Jones is swinging from a rope. The distance between the pivot point and his center of mass is 31.00m. He begins swinging from rest at an angle theta=18.00. Assuming that Indiana and the rope can be treated as a simple pendulum, what is the value of theta after 1.290s (in degrees)?
Ok so this is the farthest that any of us have gotten so far...
T= 2pi square root of L/g
theta= theta,o cos((2pi/T) t)
I think these are the equations we are supposed to use but I am still really confused on how to solve this problem. If someone could direct me in the right way and give me the right idea my WHOLE physics class would really appreciate it. Thanks!
My physics class had this problem for our homework set this week and nobody has figured it out. We asked for help from our TAs today and they didn't know how to help us either. If someone could look at this problem and tell me what they think I would really appreciate it.
Indiana Jones is swinging from a rope. The distance between the pivot point and his center of mass is 31.00m. He begins swinging from rest at an angle theta=18.00. Assuming that Indiana and the rope can be treated as a simple pendulum, what is the value of theta after 1.290s (in degrees)?
Ok so this is the farthest that any of us have gotten so far...
T= 2pi square root of L/g
theta= theta,o cos((2pi/T) t)
I think these are the equations we are supposed to use but I am still really confused on how to solve this problem. If someone could direct me in the right way and give me the right idea my WHOLE physics class would really appreciate it. Thanks!