- #1
mr_coffee
- 1,629
- 1
Hello everyone, I think i did this right, but i want to make sure this is what they want. The questions says:
In each case find a basis for and caclulate the dimension of nullA:
Here is my work and problem!
http://img207.imageshack.us/img207/2948/lastscan6ib.jpg
I just found out its wrong...but why? the book got:
{[-2 4 1 0 0 ]^T, [7 -11 0 2 1]^T}
dim(nullA) = 2.
Those kind of resemble my columns, i got
[2 -4 0 0 0] and [-7 11 2 0 0], hm...
In each case find a basis for and caclulate the dimension of nullA:
Here is my work and problem!
http://img207.imageshack.us/img207/2948/lastscan6ib.jpg
I just found out its wrong...but why? the book got:
{[-2 4 1 0 0 ]^T, [7 -11 0 2 1]^T}
dim(nullA) = 2.
Those kind of resemble my columns, i got
[2 -4 0 0 0] and [-7 11 2 0 0], hm...
Last edited by a moderator: