If I have Volts, and I need eV, how do I get that?

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eV is a unit of energy, specifically the energy gained by an electron when it accelerates through a potential difference of one volt. It is not equivalent to volts; instead, eV can be converted to joules, with 1 eV equal to 1.602 x 10^-19 joules. The discussion clarifies that potential difference relates energy to charge, making eV a useful unit for measuring energy in contexts like the photoelectric effect. The work function of a metal, which is also an energy measurement, can be expressed in eV. Understanding eV helps in various applications in physics and engineering.
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If I have Volts, and I need eV, how do I get that?

Is eV (energy format) = V (voltage format), so that if I have a value given in volts, I know that it would be the same in eV units?

I know this is a dumb question, sorry guys...:blushing:
 
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eV is a unit of energy. It is exactly the amount of kineitic energy that one electron would obtain if it accelerated across one volt of potential difference. You do not convert eV to volts. You convert eV to joules.

Since potential difference is defined as the energy per unit charge ratio you will get a unit of energy when you multiply a unit of charge times a unit of potential, hence "electron-Volt"; here the charge is the fundamental charge of the electron. A joule (unit of energy) is equivalent to a "coulomb-volt." Since 1.602 x 10^-19 coulombs is the charge of an electron, then 1eV = 1.602x10^-19 joules.
 
Thanks Chi,

yeah I suppose I will simply look at eV as the work function of a metal. i just had a mental block ;)
 
April30 said:
Thanks Chi,
yeah I suppose I will simply look at eV as the work function of a metal. i just had a mental block ;)
The work function of a metal is an amount of energy. Any amount of energy can be expressed in eV. When doing the photoelectric effect, the energy of the photon is also measured in eV, and the maximum KE of the electron is again measured in eV. Any of these amounts of energy could just as well be measured in joules, kilowatt-hours, ergs, or any other unit of energy. The eV just happens to be an appropriately small unit of energy.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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