Simple proof, just using the axioms

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SUMMARY

The discussion focuses on proving the equation (-m)(-n) = mn using basic mathematical axioms. Participants emphasize the use of the commutative and associative properties of multiplication and addition, as well as the existence of additive inverses. The proof is constructed by demonstrating that 0 = 0.0 = (1-1)(1-1) = 1 - 1.1 + 1.(-1) + (-1)(-1), leading to the conclusion that 1 = (-1)(-1). The general case is established by recognizing that -n = (-1)n.

PREREQUISITES
  • Understanding of basic mathematical axioms, including the commutative and associative properties.
  • Familiarity with the concept of additive inverses and multiplicative identity.
  • Knowledge of binary operations in mathematics.
  • Basic algebraic manipulation skills.
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  • Study the properties of binary operations in mathematics.
  • Learn about additive inverses and their role in algebra.
  • Explore proofs involving the commutative and associative properties.
  • Investigate more complex proofs in algebra using axiomatic systems.
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Students of mathematics, educators teaching algebra, and anyone interested in foundational proofs in mathematical theory.

Ed Quanta
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How could I show that (-m)(-n)= mn? The only thing I am allowed to use to prove this are the 5 basic mathematical axioms which allow for the commutative property and associative propery of the binary operations multiplication and addition;there exists an additive inverse for each integer, 1 is the multiplicative identity, and 0 is the additive identity, while mn=mp implies p=n where m is not equal to 0.
 
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presumably you know that 0.0=0

so that 0=0.0=(1-1)(1-1)=1-1.1+1.(-1)+(-1)(-1),

=>

1=(-1)(-1)

the general case now follows easily from the fact -n = (-1).n

you could do it more directly 0=m-m=n-n but you'd still have to use -n=(-1).n at some point.
 
Thanks my man
 

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