
#1
Jan907, 02:45 PM

P: 18

1. The problem statement, all variables and given/known data
The density of ice is 920 kg/m3, and that of seawater is 1030 kg/m3. What fraction of the total volume of an iceburg is exposed? 2. Relevant equations 3. The attempt at a solution I know your supposed to do volume of the ice divided by the volume of the seawater, x 100. But, I'm having trouble finding the volumes. V=m/density... but how do u find the mass? Or is there a different way of doing it. 



#2
Jan907, 03:06 PM

Mentor
P: 40,878

Compare the volume of seawater displaced to the volume of the iceberg. The fraction of the iceberg above the water level is independent of its mass or volume. (Just call the mass "m"you'll find that it will cancel out.)
To proceed, consider the forces acting on the iceberg. And consider Archimedes' principle and buoyant force. 


#3
Jan907, 03:15 PM

P: n/a

By a FBD (the iceberg is in equilibrium), so you know that the gravitational force must equal the buoyant force.



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