Register to reply

Show that the conditional statement is a Tautology without using truth tables...

by VinnyCee
Tags: conditional, statement, tables, tautology, truth
Share this thread:
Sep10-07, 05:37 PM
P: 492
1. The problem statement, all variables and given/known data

Show that [tex]\left[\neg\,p\,\wedge\,\left(p\,\vee\,q\right)\right]\,\longrightarrow\,q[/tex] is a tautology without using truth tables.

2. Relevant equations

DeMorgan's Laws, etc.

3. The attempt at a solution


by. EX 3 (see EX 8)




[tex]\left[\left(p\,\wedge\,\neg\,p\right)\,\wedge\,\left(p\,\wedge\,\neg\,q\right )\right]\,\vee\,q[/tex]


Now what?
Phys.Org News Partner Science news on
An interesting glimpse into how future state-of-the-art electronics might work
Tissue regeneration using anti-inflammatory nanomolecules
C2D2 fighting corrosion
Sep10-07, 08:09 PM
P: 617
there is an error in your first line

a -> b is logicaly equivlent to ~a or b

Register to reply

Related Discussions
Truth value of statement Calculus & Beyond Homework 4
Truth Tables and K-Maps Calculus & Beyond Homework 6
Truth tables Calculus & Beyond Homework 6
Truth of this statement? General Physics 5