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Displacement: Magnitude and Direction

by kraaaaamos
Tags: direction, displacement, magnitude
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kraaaaamos
#1
Sep20-07, 10:05 PM
P: 20
1. The problem statement, all variables and given/known data

Jim walks 100m due south, 60m due east, and then 20m due north. What is his net
displacement (both magnitude and direction)?

2. Relevant equations

I know how to find the net displacement by the magnitude of the distance...
using the d = sq. rt ( (x2-x1)^2 + (y2-y1)^2 )

but i dont know how to express the direction?

PLEASE HELP!!

3. The attempt at a solution
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mgb_phys
#2
Sep20-07, 10:16 PM
Sci Advisor
HW Helper
P: 8,954
Draw the path on graph paper then draw a line back to the start - the direction is just the angle of this line ( usually given from the horizontal x axis )
The magnitude is the length of this line.


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