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Displacement: Magnitude and Direction 
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#1
Sep2007, 10:05 PM

P: 20

1. The problem statement, all variables and given/known data
Jim walks 100m due south, 60m due east, and then 20m due north. What is his net displacement (both magnitude and direction)? 2. Relevant equations I know how to find the net displacement by the magnitude of the distance... using the d = sq. rt ( (x2x1)^2 + (y2y1)^2 ) but i dont know how to express the direction? PLEASE HELP!! 3. The attempt at a solution 


#2
Sep2007, 10:16 PM

Sci Advisor
HW Helper
P: 8,953

Draw the path on graph paper then draw a line back to the start  the direction is just the angle of this line ( usually given from the horizontal x axis )
The magnitude is the length of this line. 


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