Proofs for Triangle Congruency: L is the Midpoint of Line JN

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L is the midpoint of line JN, and the problem involves proving that triangle PKJ is congruent to triangle QMN given that line PJ is congruent to line QN, line PL is congruent to line QL, and angles PKJ and OMN are right angles. The initial response highlights a lack of clarity in the problem setup, suggesting that additional information or a diagram is necessary for proper understanding. The responder expresses difficulty in visualizing the triangles based on the provided details. A request for a visual representation, such as a simple drawing, is made to aid in solving the problem. Clear communication and additional context are essential for progressing with the proof.
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Homework Statement


L is the midpoint of line JN, line PJ congruent line QN, line PL congrent to LINe ql, angel pkj and angle omn are ryte angels.
prove: triangle PKJ congruent to TRiangle QMN


Homework Equations


it mite be line segment, because it has a line on top of it.. no arrows.. sorry, I am not smart in geometry...=[


The Attempt at a Solution

 
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Welcome to PF. You forgot to give us some information. Like: I understand that PKJ and QMN are triangles, but if I just draw two random triangles then J and N are not connected by a line and after some attempts I can't seem to draw a situation in which all the given information makes sense. Can you supply a picture somehow, even a simple attachment made in Paint would do.
 
you need to show us more information and possibly your thoughts on the problem.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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